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Kruskov's theorem for a scalar conservation law

The scalar Cauchy problem
\begin{displaymath}
u_t + f(u)_x = 0,    f \in C^1({\mathbb{R}})
\end{displaymath} (1)

with initial condition
\begin{displaymath}
u(0,x) = u_o(x),    u_o \in L^\infty({\mathbb{R}})
\end{displaymath} (2)

has a unique entropy solution

\begin{displaymath}
u \in L^\infty({\mathbb{R}}_+ \times {\mathbb{R}})
\end{displaymath}

which fulfills (important for numerics)
  1. $\vert\vert u(t, \cdot)\vert\vert _{L^\infty} \le \vert\vert u_o \vert\vert _{L^\infty}$, a.e. in $t \in
{\mathbb{R}}_+$ (Stability)
  2. if $u_o \ge v_o$ a.e. in ${\mathbb{R}}$, then

    \begin{displaymath}
u(t, \cdot) \ge v(t, \cdot)    \textrm{ a.e. in } {\mathbb{R}}, \textrm{ a.e. in t}
\in {\mathbb{R}}_+
\end{displaymath}

    (monotone)
  3. if $u_o \in BV({\mathbb{R}})$ then

    \begin{displaymath}
u(t, \cdot) \in BV({\mathbb{R}})    \textrm{ and }    TV(u(t, \cdot)) \le TV(u_o)
\end{displaymath}

    (TV-Diminishing)
  4. if $u_o \in L^1({\mathbb{R}})$ then

    \begin{displaymath}
\int_{{\mathbb{R}}} u(t,x) \textrm{d}x = \int_{\mathbb{R}}u_o(x) \textrm{d}x,    \textrm{ a.e. in } t
\in {\mathbb{R}}_+
\end{displaymath}

    (conservation)
  5. if $u$, $v$ are two entropy solutions, $u_o, v_o \in L^\infty$ and

    \begin{displaymath}
M = \max\{ \vert f^\prime(\phi) \vert : \vert \phi \vert \le...
...ert\vert _{L^\infty},
\vert\vert v_o\vert\vert _{L^\infty}) \}
\end{displaymath}

    then

    \begin{displaymath}
\int_{\vert x\vert \le R} \vert u(t,x) - v(t,x) \vert \textr...
...ert x\vert \le R + Mt} \vert
u_o(x) - v_o(x) \vert \textrm{d}x
\end{displaymath}

    (finite domain of dependence)


Praveen. C, last updated on 18-February-2005